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Question 5.14: If the bar magnet in exercise 5.13 is turned around by 180º, where will the new null points be located?Class 12 - Physics - Magnetism And Matter Magnetism And Matter Page-201

Answer»

When the bar MAGNET is turned through 180°, neutral points would lie on equatorial line, so that magnetic field at equatorial line = HORIZONTAL COMPONENT of earth's magnetic field
e.g., B_2=\frac{\mu_0}{4\pi}\frac{M}{d_2^3}=B_H----(1)

in PREVIOUS question, exercise 5.13
magnetic field at axial line =horizontal component of earth's magnetic field.
e.g.,B_1=\frac{\mu_0}{4\pi}\frac{2M}{d_1^3}=B_H----(2)

from equations (1), and (2),
\frac{\mu_0}{4\pi}\frac{M}{d_2^3}=\frac{\mu_0}{4\pi}\frac{2M}{d_1^3}\\\\\therefore\:d_2^3=\frac{d_1^3}{2}

given, d_1=14cm
so,d_2^3=\frac{14^3}{2}
d_2=11.1cm


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