Question 4please slove it

1.	Question 4please slove it
Answer» Step-by-step explanation: As BP = BC BPC Is an isosceles ∆ Now.Let angle BPC be the x° then, angle BCP =x According to SUM property of A triangle ang. BPC+angBCP+angPBC = 180° x°+x°+90° = 180° (ang.PBC = 90° as..Abcd is a RECTANGLE) 2x= 90° x= 45° ang..bpc= 45°=ang..bcp Now, ang. BCD= ang. BCP+ang.PCD 90°= 45°+ ang. PCD (ANG.Bcd=90° as abcd is a rectangle& Ang. Bcp= 45 ° from above ) ANG. PCD= 45°

Answer»

Step-by-step explanation:

As BP = BC

BPC Is an isosceles ∆

Now.Let angle BPC be the x° then, angle BCP =x

According to SUM property of A triangle

ang. BPC+angBCP+angPBC = 180°

x°+x°+90° = 180° (ang.PBC = 90° as..Abcd is a RECTANGLE)

2x= 90°

x= 45°

ang..bpc= 45°=ang..bcp

Now, ang. BCD= ang. BCP+ang.PCD

90°= 45°+ ang. PCD (ANG.Bcd=90° as abcd is a rectangle& Ang. Bcp= 45 ° from above )

ANG. PCD= 45°

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Question 4please slove it​

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Question 4please slove it