Question 3ABC is an isosceles triangle with AB = AC and D is a point on BC such that AD⊥BC (see figure). To prove that ∠BAD=∠CAD, a student proceeded as follows.In ΔABD and ΔACD, we have AB= AC [given]∠B=∠C [because AB=AC]And ∠ADB=∠ADCTherefore,ΔABD≅ΔACD [by AAS congruence rule]So,∠BAD=∠CAD [by CPCT]What is the defect in the above arguments?

Question 3ABC is an isosceles triangle with AB = AC and D is a point o

1.	Question 3ABC is an isosceles triangle with AB = AC and D is a point on BC such that AD⊥BC (see figure). To prove that ∠BAD=∠CAD, a student proceeded as follows.In ΔABD and ΔACD, we have AB= AC [given]∠B=∠C [because AB=AC]And ∠ADB=∠ADCTherefore,ΔABD≅ΔACD [by AAS congruence rule]So,∠BAD=∠CAD [by CPCT]What is the defect in the above arguments?
Answer» Question 3 ABC is an isosceles triangle with AB = AC and D is a point on BC such that $A D ⊥ B C$ (see figure). To prove that $∠ B A D = ∠ C A D$ , a student proceeded as follows. In $Δ A B D$ and $Δ A C D$ , we have AB= AC [given] $∠ B = ∠ C$ [because AB=AC] And $∠ A D B = ∠ A D C$ Therefore, $Δ A B D ≅ Δ A C D$ [by AAS congruence rule] So, $∠ B A D = ∠ C A D$ [by CPCT] What is the defect in the above arguments?