1.

Question 31The value of (3x3+9x2+27x)÷3x isa) x2+9+27xb) 3x3+3x2+27xc) 3x3+9x2+9d) x2+3x+9

Answer» Question 31



The value of (3x3+9x2+27x)÷3x is

a) x2+9+27x

b) 3x3+3x2+27x

c) 3x3+9x2+9

d) x2+3x+9




Discussion

No Comment Found