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QUESTION 2Prove the identity: sin 0 + cos6 e + 3 sind e cos2 0 = 1. |
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Answer» Answer: = (sin2 θ – cos2 θ)(sin2 θ + cos2 θ) = (sin2 θ – cos2 θ) × 1 = sin2 θ – cos2 θ = R.H.S. = sin2 θ – (1 – sin2 θ) = sin2 θ – 1 + sin2 θ = 2 sin2 θ – 1 = R.H.S. = 2(1 – cos2 θ) – 1 = 2 – 2 cos2 θ – 1 = 1 – 2 cos2 θ = R.H.S. Hence PROVED. |
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