Saved Bookmarks
| 1. |
Question 27: In the circuit shown below, the voltmeter reads 10 V. (a) What is the combined resistance ? (b) What current flows ? (c) What is the p.d. across 2 Ω resistor ? (d) What is the p.d. across 3 Ω resistor ? Lakhmir Singh Physics Class 10 |
|
Answer» a) 5ohmb) 2ampc) 4Vd) 6VExplanation:Although the above given question has not given the circuit, but from the question we can conclude that the voltage is 10V and two resistances are 2 ohm and 3 ohm respectively.a) When two resistors are CONNECTED in series combination, the combined resistance given by them would be (2+3)ohm = 5ohm.b) We know that the amount of voltage = Amount of current passed × Resistance given.So , I = V/ R I = 10/5 [ combining resistance of two resistors in series combination, 2+3 =5] Therefore I = 2 amp.c) At 2 ohm resistor, the potential DIFFERENCE is :V= I×R So, 2×2= 4V.d) At 3 ohm resistor, the potential difference is:V= 2×3 =6V |
|