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Question 10please slove it |
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Answer» Answer:angle DCB=120°,angle CAB=50°, angleDAC=79° Step-by-step explanation: GIVEN that ABCD is a parallelogram we know that in a parallelogram opposite angles are equal. angle ADC =angle ABC=60° In ∆ABC angle ABC+ angle BAC +angle ACB=180°(Since sum of the angles of a traingle =180°) 60°+angle BAC+70°=180° 130°+angle BAC=180° angle BAC=180°-130° angle BAC=50° In a parallelogram opposite sides are parallel so AD||CB angle ACB= angle DAC=70° (since interior alternate angles are equal) SIMILARLY AB||DC angle DCA= angle BAC=50° angle DCB=Angle DCA +angle ACB angle DCB=50°+70° angle DCB=120° |
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