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Question 10a) A (20, 0) and B (10,- 20) are two fixed points. Find the co-ordinates of point P in AB suchthat AB 3PB.131 |
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Answer» Given, 3PB = ABAB/PB = 1/3AB - PB/PB = 3 - 1/1 = 2/1AP/PB = 2/1 Using section formula coordinates of P areP(x, y) = P(2*10 + 1*20)/2+1, 2*-20 + 1*0/2+1)= P(40/3, - 40/3) |
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