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Question 1- Water flows in a tank 150m × 100m at the base through a pipe whose cross-section is 2 dm × 1.5 dm at the speed of 15 km/h. In what time, will the water be 3m deep?Question 2- A solid cylinder has total surface area of 462 sq cm. Its curved surface area is one-third of its total surface area. Find the volume of the cylinder. (Assume π=22/7). |
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Answer» Step-by-step explanation: Question 1- Volume of water in the tank, when depth is of 3 m, V = 150 × 100 × 3 = 45000 m3 Rate of volume of water FLOWING = 2 × 1.5 × 10-2 × 15000 m3/hr = 450 m3/hr Thus, time taken = 45000/450 hr = 100 hours
Question 2- Curved SURFACE area = TOTAL surface area / 3. Curved surface area = 462/3 = 154. Rest of area = 462 - 154 = 308. 2πr^2 = 308. r^2 = 308 x 7 / 44 = 49. r = 7. 2πrh = 154. h = 154 / 2 x 22 = 7/2. Volume = πr^2 h = (22/7) x (7^2) x (7/2) = 539. Volume = 539 cm^3.... Please FOLLOW me.. |
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