1.

Ques 1: Calculate the molarity of a sulphuric acid solution in which the molefraction of water is 0.85.​

Answer»

EXPLANATION:

mol FRACTION of WATER in SOLUTION = 0.85

So mol of ACID = 1-0.85 = 0.15

Now

m= nw×molecularwtofwater

1000×molofacid

m= 0.85×18

1000×0.15

=9.8mol/kg



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