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Que. 15 if "P13: n1P12 3:4 then find the value of c1?13 : |
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Answer» NP13 :(n+1)P 12 = 3 : 4 4( nP3) = 3 { (n+1) P 12) 4 ( n !/ (n-13) ! ) = 3 { (n+1)! / (n+1-12)!}4 n !/ (n-13) ! = 3 ( (n+1)!/(n-11)!)4.(n-11)! / (n-13)! = 3 (n+1)! / n!4. (n-11)(n-12) = 3(n+1)4 (n² - 23n + 132) = 3n + 34n² - 92n + 528 - 3n -3 = 04x² - 95n + 525 = 0(4n - 35)(n- 15)= 04n -35 = 0n = 35/4 n -15 =0n= 15 Like my answer if you find it useful! |
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