Saved Bookmarks
| 1. |
Quantity B: Two coins are tossed at the same time. Find the probability of getting two heads.1). Quantity A > Quantity B2). Quantity A < Quantity B3). Quantity A ≥ Quantity B4). Quantity A ≤ Quantity B |
|
Answer» Statement I: Total no. of balls = 10 + 12 + 20 = 42 Number of red and BLUE balls = 10 + 12 = 22 ∴ The SUM of probabilities of finding a red and blue balls = 22/42 = 11/21 ∴ Quantity A = 11/21 ≈ 0.52 Statement II: Probability of getting a head = 1/2 ∴ Probability of getting two heads = 1/2 × 1/2 = 1/4 ∴ Quantity B = 1/4 = 0.25 ? 0.52 > 0.25 ∴ Quantity A > Quantity B |
|