1.

Quantity B: Two coins are tossed at the same time. Find the probability of getting two heads.1). Quantity A > Quantity B2). Quantity A < Quantity B3). Quantity A ≥ Quantity B4). Quantity A ≤ Quantity B

Answer»

Statement I:

Total no. of balls = 10 + 12 + 20 = 42

Number of red and BLUE balls = 10 + 12 = 22

∴ The SUM of probabilities of finding a red and blue balls = 22/42 = 11/21

∴ Quantity A = 11/21 ≈ 0.52

Statement II:

Probability of getting a head = 1/2

∴ Probability of getting two heads = 1/2 × 1/2 = 1/4

∴ Quantity B = 1/4 = 0.25

? 0.52 > 0.25

∴ Quantity A > Quantity B


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