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Quadratic equationFmd the value of k for which the quadratic equation (k + 4)x' + (k+1)x + 1 = 0 has two realequal roots. |
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Answer» Step-by-step explanation: GIVEN it has TWO real roots MEANS DISCRIMINANT(D) > 0. and. D=b^2-4ac here a=K+4 , b=k+1 , c=1 D= (k+1)^2-4(k+1) (1) D=k^2+1+2k-4k-4 D=k^2-2k-3 then by factorising we get =k^2-3k+k-3 =k(k-3)+1(k-3) k=(k+1)(k-3) k=(-1,3) |
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