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Q4): The value of limk→0f(2, k) − f(2,0)kis equal toa): fx(2,0) b): fy(2,0)c): fx(0,2) d): fy(0,2) |
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Answer» Answer is 3/2 Step-by-step explanation: Here , function is continuous , So, left limit and right limit boh are equal and EQUALS to the VALUE of f(x) at x=0 Therefore x→0 lim
f(x)= x→0 lim
x 2
x 2
−cosx
Solving limit by derivative approach, => x→0 lim
f(x)= x→0 lim
2x e x 2
.2x+sinx
=> x→0 lim
f(x)= x→0 lim
2x 2e x 2
+e x 2
.x 2 +cosx
Putting x=0, we get => f(0)= 2 2+0+1
= 2 3
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