1.

Q33. Prove that : tan10® . tan15° . tan75° . (पाप छे0 = 1. i e 3 g.b R

Answer»

tan 10.tan 15.tan 75. tan 80

= cot(90 - 10).cot(90 - 15).tan 75.tan 80

= cot 80.cot 75.tan 75.tan 80

= (1/tan 80).(1/tan 15).tan 75.tan 80

= 1

Hence proved



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