1.

.Q3. PQ and PR are tangents to a circle with centre Alf ZQPA=27° then find ZQAR​

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ANSWER:

hey MATE here is your answer...

Step-by-step explanation:

ΔAQP+ΔARP

AP=APcommon

∠Q=∠R[90

]

AQ=AR[RADII]

So1∠QPA=∠RPA=27

∠P+∠Q+∠A+∠R=360

54+90+∠A+90=360

∠A=360

−180−54

∠A=180−54

∠A=126

∠QAR=126

ANS.



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