1.

.Q3. PQ and PR are tangents to a circle with centre Alf ZQPA=27° then find ZQAR​

Answer»

ANSWER:

hey MATE here is your answer...

Step-by-step explanation:

ΔAQP+ΔARP

AP=APcommon

∠Q=∠R[90

∘

]

AQ=AR[RADII]

So1∠QPA=∠RPA=27

∘

∠P+∠Q+∠A+∠R=360

∘

54+90+∠A+90=360

∘

∠A=360

∘

−180−54

∠A=180−54

∠A=126

∘

∠QAR=126

∘

ANS.



Discussion

No Comment Found

Related InterviewSolutions