Q3:HCF of 2 and 12 isO a) 12Ob) 24Oc) 2

1.	Q3:HCF of 2 and 12 isO a) 12Ob) 24Oc) 2
Answer» HELLO, how are you? WELL, here you can solve this question (that the statement of the same ask for we find the highest COMMON factor of 2 and 12) using the method of the prime factorization. See the resolution of the same below in the practice. $\text{[math]}$ $\begin{array}{r\|l}2,12&2\\1,12\end{array}$ $\text{[math]}$ Now, that you factored both by 2 we will find the highest common factor. $\text{[math]}$ $\boxed{\mathsf{HCF=2}}$ $\text{[math]}$ Therefore, with all this conjecture that make with objective of find the highest common factor of 2 and 12 we have that the the highest common factor is 2. $\text{[math]}$ Important note : For you to use this method, both number need to be divisible by the same number, how can see 2 and 12 are divisible by 2. $\text{[math]}$ $\text{[math]}$ I have COLLABORATED !

Answer»

HELLO, how are you?

WELL, here you can solve this question (that the statement of the same ask for we find the highest COMMON factor of 2 and 12) using the method of the prime factorization. See the resolution of the same below in the practice.

$\text{[math]}$

$\begin{array}{r|l}2,12&2\\1,12\end{array}$

$\text{[math]}$

Now, that you factored both by 2 we will find the highest common factor.

$\text{[math]}$

$\boxed{\mathsf{HCF=2}}$

$\text{[math]}$

Therefore, with all this conjecture that make with objective of find the highest common factor of 2 and 12 we have that the the highest common factor is 2.

$\text{[math]}$

Important note : For you to use this method, both number need to be divisible by the same number, how can see 2 and 12 are divisible by 2.

$\text{[math]}$

I have COLLABORATED !

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