Saved Bookmarks
| 1. |
Q22: In the given figure, a circle touches the side BC of AABC at P and touches AB and AC producedat Q and R respectively. If AQ 5 cm, find the perimeter of ΔABC. |
|
Answer» AQ = AR = lengths of tangents from point A to the ex-circle of triangle ABC.BQ = BP = lengths tangents from B onto the excircle.CR = CP = lengths of tangents from C onto the excircle. AQ = AB + BQ = AB + BP AR = AQ = AC + CR = AC + CPAQ + AR = 2 AQ = AB + BP + PC + CA = perimeter of triangle ABC So perimeter = 2 * 5 cm = 10 cm Like my answer if you find it useful! |
|