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Q2 from this photo pls help me |
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Answer» Answer: 2)sin A = √3cosA sinA/COSA = √3 tanA = √3. [tan X = sin X /cos X] tan A = tan 60° A = 60°. 3)sin X + cos X = 1 squaring on both SIDES , sin²x + cos²x + 2 sin X · cos X = 1 we know that sin²x + cos²x = 1. 1 + 2 sin X · cos X = 1 2 sin X · cos X = 0 sin X · cos X = 0/2 sin X · cos X = 0. hope it helps you |
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