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Q10. In figure, BA 1 ED and BCI EF. Show that LABC =DEF.Fr |
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Answer» Given BA||ED, so BA|| DF ( extension of P to F)∠ABC=∠ DPC( corresponding angle)...(1)Given BC||EF,∠DEF=∠DPC(corresponding angle)...(2)From (1) and (2) we get,∠ABC = ∠DEF Proved |
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