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Q1.If one root of the equation xsquare+7x+k=0 is -2, then find the value of k and the other root. |
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Answer» ONE root of x²+7x+K = 0 is -2 therefore, (-2)² + 7(-2)+k = 0 4 - 14 + k = 0 k = 10 The equation is x²+7x+10 = 0 Product of the ROOTS = αβ = 10 (-2) β = 10 β = -5 the other root is -5 |
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