1.

Q1) ABC and AMP are two right triangles, right angled at B and M respectively. Prove that: (i)∆ABC~∆AMP (ii) CA/PA=BC/MP

Answer»

Step-by-step explanation:

In △ABC and △AMP,

∠ABC=∠AMP=90

o

∠A is common

∴ By AA criterion of SIMILARITY, △ABC ∼ △AMP

PA

CA

=

MP

BC

(CORRESPONDING SIDES of Similar Triangles)

Hence Proved



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