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Q1) ABC and AMP are two right triangles, right angled at B and M respectively. Prove that: (i)∆ABC~∆AMP (ii) CA/PA=BC/MP |
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Answer» Step-by-step explanation: In △ABC and △AMP, ∠ABC=∠AMP=90 o
∠A is common ∴ By AA criterion of SIMILARITY, △ABC ∼ △AMP ∴ PA CA
= MP BC
(CORRESPONDING SIDES of Similar Triangles) Hence Proved |
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