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Q.The sum of the digits of a two digit number is 5. The digit obtained byincreasing the digit in ten's place by unity is one-eighth of the number. Find thenumber. |
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Answer» Let the digit in unit place be y and digit in tens place be x the number will be 10x+y therefore from first condition x+y=5.......(1) from second condition x+1=1/8*10x+y therefore 8x+8=10x+y 8=10x-8x+y 8=2x+y....................................(2) now subtracting equation (1) from (2) 2x+y=8-(x+y)=-5 x =3now putting value of x in equation (1) 3+y=5 y=5-3 y =2 so the number is 32 |
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