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Q.The sum of the digits of a two digit number is 5. The digit obtained byincreasing the digit in ten's place by unity is one-eighth of the number. Find thenumber.​

Answer»

Let the digit in unit place be y and digit in tens place be x

the number will be  10x+y

therefore from first condition x+y=5.......(1)

from second condition x+1=1/8*10x+y

therefore 8x+8=10x+y                8=10x-8x+y                   8=2x+y....................................(2)

now   subtracting  equation  (1) from (2)

  2x+y=8-(x+y)=-5     x   =3now putting  value of x in equation (1)

3+y=5    y=5-3   y  =2 

so the number is 32



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