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Q. The particular Integral of D.E. \( (D-1) y=x^{2}+5 x+7 \) is |
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Answer» P.I. = \(\frac{1}{D-1}(x^2+5x+7)\) = \(-\frac{1}{D-1}(x^2+5x+7)\) = - (1+D+D2+D3+...) (x2+5x+7) (∵\(\frac{1}{1-D}\) = 1+D+D2+...) = - ((1+D+D2)x2 + (1+D) 5x+7) = - (x2+2x+2+5x+5+7) = - (x2+7x+14). |
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