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Q.The particle position as a function of time is given as x = 5t ^ 2 - 9t + 3 Find out the minimum value of position co-ordinate. |
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Answer» x = 5t ^ 2 - 9t + 3 = 5(t^2-9/5t+3/5) =5{t^2-2×t×9/10+(9/10)^2} -81/20+3 =5(t-9/10)^2-21/20 So minimum value of x will be obtained when t=9/10 Hence minimum value of the position coordinate will be x=21/20=-1.05 |
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