Q:-solve and find the value of x2(3x+1)=12+2(4x+3)

1.	Q:-solve and find the value of x2(3x+1)=12+2(4x+3)
Answer» $\green{\bold{\underline{ ✪ UPSC-ASPIRANT✪ }}}$ $\red{\bold{\underline{\underline{QUESTION:-}}}}$ Q:-SOLVE and FIND the VALUE of x 2(3x+1)=12+2(4x+3) $\huge\tt\underline\blue{Answer }$ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _✍️ ══════════XXX═════════════ $⟹2(3x + 1) = 12 + 2(4x + 3)$ $⟹6x + 2 = 12 + 8x + 6$ $⟹2 - 12 - 6 = 8x - 6x$ $⟹ - 16 = 2x$ $⟹ \frac{ - 16}{2} = 2x$ $⟹x = - 8$ CHECK:- $⟹2(3( - 8) + 1) = 12 + 2(4( - 8) + 3)$ $⟹2( - 24 + 1) = 12 + 2( - 32 + 3)$ $⟹2( - 23) = 12 + 2( - 29)$ $⟹ - 46 = 12 - 58$ $⟹ - 46 = - 46$ ══════════XXX═════════════ HOPE IT HELPS YOU.. _____________________ THANKYOU:)

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