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Q.No 3 The average of five numbers is 496. If two of them are 117 and 140, find theaverage of remaining three numbers.(a 239 (b) 717 (c) 741 (d) 637 |
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Answer» Average of 5 numbers= sum of 5 numbers /5Sum of 5 no. = 496x5 = 2480 If two no. are 117 and 140Sum of remaining 3 no. = 2480 - 257= 2223Average of remaining 3 no. = 2223/3= 741 |
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