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Q.No 3 The average of five numbers is 496. If two of them are 117 and 140, find theaverage of remaining three numbers.(a 239 (b) 717 (c) 741 (d) 637

Answer»

Average of 5 numbers= sum of 5 numbers /5Sum of 5 no. = 496x5 = 2480

If two no. are 117 and 140Sum of remaining 3 no. = 2480 - 257= 2223Average of remaining 3 no. = 2223/3= 741



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