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Q.N.3-On dividing x3+3x2+3x+1by x=0 then we get remainder(а) -9(b) 1 (с)-3(d) 0​

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Question:-

On dividing x3+3x2+3x+1by X=0 then we GET REMAINDER

(а) -9

(b) 1 (с)-3

(d) 0

Required Answer:-

Remainder = 1

Solution:-

Apply remainder theorem, we get

=> x = 0

Replacing x by 0 we get,

=> x^3 + 3x^2 + 3x + 1

=> (0)^3 + 3(0)^2 + 3(0) + 1

=> 0 + 0 + 0 + 1

=> 1

Hence,

Remainder = 1


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