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Q) Let b benon- zero real number. Suppose thequadratic equation 2x^2 + bx + 1/b = 0 has two distictreal rools. Then,(A)b+1/b>5/2(B) b+1/b |
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Answer» Step-by-step explanation: The given EQUATION is 2x2+bx+b1=0, comparing it with Ax2+Bx+C=0. We get A=2,B=b and C=b1 ⇒ B2−4AC=(b)2−4(2)×b1 ⇒ B2−4AC=b2−b8 Now, Discriminant>0 [ For REAL roots ] b2−b8>0 [ For real roots ] bb3−(2)3>0 b(b−2)(b2+2b+4)>0 b2+2b+4 always positive bb−2>0 b−2>0,b>0 and b−2<0,b<0
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