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Q is any point on the circle `x^(2) +y^(2) = 9. QN` is perpendicular from Q to the x-axis. Locus of the point of trisection of QN isA. `4x^(2) +9y^(2) = 36`B. `9x^(2) +4y^(2) = 36`C. `9x^(2) +y^(2) = 9`D. `x^(2) +9y^(2) = 9` |
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Answer» Correct Answer - A::D Let `Q = (3 cos theta, 3 sin theta) rArr N =(3 cos theta,0)` Point of trisection are `(3cos theta, sin theta)` or `(3 cos theta,2 sin theta)`. Locus is `(x^(2))/(9) + y^(2) =1` or `(x^(2))/(9) + (y^(2))/(4) =1` |
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