Q. IN THE GIVEN FIGURE. AB II CD AND 0 IS THE CENTER OF THE CIRCLE. IF

1.	Q. IN THE GIVEN FIGURE. AB II CD AND 0 IS THE CENTER OF THE CIRCLE. IF ∠ADC= 25°, THEN THE MEASURE OF ∠AEB IS
Answer» ANSWER: In the GIVEN figure join AC and BD then ∠CAD=∠CBD=90 o ∵ ANGLE is FORMED by diameter. Also AB∣∣CD ∴∠BAD=∠ADC=25 o ∠BAC=∠BAD+∠CAD=25+90=115 o ∴ ∠ADB=180 o −25−∠BAC=40 o Also, ∠AEB=∠ADB=40 o Angle subtended by same chord on the circle are equal. Step-by-step explanation:

Q. IN THE GIVEN FIGURE. AB II CD AND 0 IS THE CENTER OF THE CIRCLE. IF ∠ADC= 25°, THEN THE MEASURE OF ∠AEB IS

Answer»

ANSWER:

In the GIVEN figure join AC and BD then ∠CAD=∠CBD=90

∵ ANGLE is FORMED by diameter.

Also AB∣∣CD

∴∠BAD=∠ADC=25

∠BAC=∠BAD+∠CAD=25+90=115

∴ ∠ADB=180

−25−∠BAC=40

Also, ∠AEB=∠ADB=40

Angle subtended by same chord on the circle are equal.

Step-by-step explanation:

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Q. IN THE GIVEN FIGURE. AB II CD AND 0 IS THE CENTER OF THE CIRCLE. IF ∠ADC= 25°, THEN THE MEASURE OF ∠AEB IS

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