Q: In the given circuit ,the potential difference between point A and

1.	Q: In the given circuit ,the potential difference between point A and B is 18V and charge on 2uF capacitor is 24uC . The energy stored in capacitor C is?
Answer» Answer: 1 μF Explanation: Voltage ACROSS 2μFcapacitor is 2/24=12V So, voltage across 6μF CAPACITOR is 18−12=6V Hence, charge on 6μF capacitor 6×6=36μC So, charge on C capacitor =36−24=12μC The VALUE of C is C= 12/12 =1μF Hope it helps. If so, then please make me as Brainliest answer. Thank you Thanks Rate⭐⭐⭐⭐⭐

Q: In the given circuit ,the potential difference between point A and B is 18V and charge on 2uF capacitor is 24uC . The energy stored in capacitor C is?

Answer»

Answer:

1 μF

Explanation:

Voltage ACROSS 2μFcapacitor is 2/24=12V

So, voltage across 6μF CAPACITOR is 18−12=6V

Hence, charge on 6μF capacitor 6×6=36μC

So, charge on C capacitor =36−24=12μC

The VALUE of C is

C= 12/12 =1μF

Hope it helps.

If so, then please make me as Brainliest answer.

Thank you

Thanks

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Q: In the given circuit ,the potential difference between point A and B is 18V and charge on 2uF capacitor is 24uC . The energy stored in capacitor C is?​

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Q: In the given circuit ,the potential difference between point A and B is 18V and charge on 2uF capacitor is 24uC . The energy stored in capacitor C is?