a+50°+50°=180a=80°and we know that angle subtended by an arc at centre is double angle subtended by it at any point on the remaining part of the circlesince a/2=b=80/2=40°

a=80as, 180-(50+50)180-100=80b=40

a=80180-(50+50)180-100=80b=40

a = 50 - 180a = 130

b = 130 - 180 b = 50

a=80 ,b=40 is the correct answer

40° is 100% guaranteed correct answer

a=80° and b=40° is correct answer

a=80 b=40 is the correct and best answer

50+50+a=180। so a=80। and b=40

So easy...a=80°and b=40°.........▪︎▪︎(half of angle a)

a=80° and b=40° is the right answer

a=80°180° - (50+50) 180-100=80b=40° answer

a=80180- (50+50)180- 100=80b=40

angle a =80angle b=40

50+50+x=180(because triangle three side of is add 180)

a=80as,180-(50+50)b=40

given an angle 50 ° equal front angle because both sides are equaltherefore a=80°b=1/2 of ab=40

70° is the correct answer

a= 80 and b= 40..........

A=80 B=40is the best answer

a=80as, 180-(50+50)180-100=80b=40.

a=80'andb=80'(acchuli AK hi vartya khand ke angle =hote hai)

a=80b=40.................

a=80b=40 uis the correct answer.

a= 80,b=40 is answer

50+50+a = 180=100+a=180a=180-100 a= 80 ans

50 + 50 + a = 180 (angle sum prop. of traingle) 100 + a = 180a = 180 - 100a = 80

b = 80/2 = 40 ( angle subtended by an arc at Centre is double angle subtended by it at any remaining part of the circle)

a=80as,180-(50+50)180-100=80b=40

त्रिभुज के तीनों कोनो मान=180तो कोन A+B+C=180 A+50+50=180 A+100=180 A=180-100 A=80

A-80 B-40 is right answer

a=80°and b=40° that is answer that question

a=80° and b=40 that is answer to your question

a = 80° and b = 40°{because 50+50+a=180°= a = 80°}

answer for this question is a=80,b=40

a ki value 80 b ki value 90