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Q.6,Find the centre and radius of the circle x2 + y2-6x-8y-24 = 0 |
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Answer» Comparing with standard equation hence,Standard equation is x^2+y^2+2gx+2fy+c=0hence radius is √g^2+f^2-c and centre is (-g,-f)hence g is -3f is -4c is -24hence radius is √(3)^2+(4)^2-(-24)=√9+16+24=√49=7Hence centre is (3,4) |
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