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Q. 4. The half life life of a firs order reaction is 6.0 How long will it take for the concentration of reactant to decrease from 0.8 M to 0.25 M? |
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Answer» ong>Explanation: The half LIFE of a FIRST order REACTION is given by the equation, t(1/2) = 0.693/k 6 = 0.693/k k = 0.693/6 = 0.1155 MIN^(-1) Therefore 0.1155 = (2.303/t)log(3.2) 0.1155 = (2.303/t)*0.505 t = 10.0694 hrs Hope this helps you |
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