1.

Q. 4. The half life life of a firs order reaction is 6.0 How long will it take for the concentration of reactant to decrease from 0.8 M to 0.25 M?​

Answer»

ong>Explanation:

The half LIFE of a FIRST order REACTION is given by the equation,

t(1/2) = 0.693/k

6 = 0.693/k

k = 0.693/6 = 0.1155 MIN^(-1)

Therefore

0.1155 = (2.303/t)log(3.2)

0.1155 = (2.303/t)*0.505

t = 10.0694 hrs

Hope this helps you



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