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Q.3 If P(Y)= 4+3y-Y2+5y3, Find P(3)​

Answer»

<P>Step-by-step explanation:

p(y)=4+3y-y²+5y³

     =5y³-y²+3y+4

p(0)=5y³-y²+3y+4

     =5*(0)³-(0)²+3*0+4

     =5*0-0*3+0+4

     =0-0+0+4

     =4

p(1)=5y³-y²+3y+4

    =5*(1)³-(1)²+3*1+4

    =5*1-1+3+4

    =5-1+7

    =4+7

    =11

p(2)=5y³-y²+3y+4

     =5*(2)³-(2)²+3*2+4

     =5*8-4+6+4

     =40-4+10

     =36+10

     =46

so, p(0)=4 , p(1)=11 , p(2)=46


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