1.

Q.2- A plastic box 1.5 m long. 1.25 m wide and 65 cm deep is to be made. It is opened at the top.Ignoring the thickness of the plastic sheet, determine the area of the sheet required for making thebox ) The cost of sheet for it, f a sheet measuring 2 1m costs Rs. 20​

Answer»

★ Answer ★

↠The area of the sheet required for making the box is 5.45 m²

↠The cost of sheet is Rs. 109 , if a sheet measuring 1 m² COSTS Rs. 20.

Step by step Explanation

GIVEN :-

  • Length = 1.5 m
  • Breadth = 1.25 m
  • Height = 65 cm

Converting it in " cm "

  • Length of the box in cm = 150 cm
  • Width of the box in cm = 125 m

★ Have to FIND :-

  1. The area of the sheet required for making the box.
  2. The cost of sheet for it, if a sheet measuring 1 m² costs Rs. 20.

Diagram:-

\setlength{\unitlength}{6}\begin{picture}(10,6) \put(0,1){\line(0,1){10}}\put(0,1){\line(1,0){10}}\put(10,1){\line(0,1){10}}\put(0,11){\line(1,0){10}}\put(0,11){\line(1,1){5}}\put(10,11){\line(1,1){5}}\put(10,1){\line(1,1){5}}\put(0,1){\line(1,1){5}}\put(5,6){\line(1,0){10}}\put(5,6){\line(0,1){10}}\put(5,16){\line(1,0){10}}\put(15,6){\line(0,1){10}}\put(2, - 0.5){$ \bf 1.5 m $}\put(13,3){$ \bf 1.25 m $}\put( - 5, 5){$ \bf 0.65 m $}\end{picture}

★ Solution:-

As we know , the box is in cuboidal shape.

Now, As according to the Question

Box is opened at the top.

The area of the sheet required for making the box.

Using the FORUMULA of T.S.A

↬ Area = TSA - Area of Top

2(lb + bh + hl) - lb

↬ 2lb + 2bh +2hl - lb

↬ lb + 2bh + 2hl

↬Area =( 150 × 125 ) + [ 2 × ( 125 × 65 ) ] + [2 × (65 × 150)]

↬ 18,750 + (2 × 8,125) + (2 × 9,750)

↬ 18,750 + 16,250 + 19,500

54,500 cm²

Firstly converting it into m²

Area of sheet in m² = 5.45 m²

Now, let's find out the cost of sheet for it,

1m² costs given as Rs 20

Then,

Total Cost of Sheet = Area of sheet × Cost

↬ 5.45 m² × Rs. 20

↬ Rs. 109

➤ Cost of Sheet is Rs. 109

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