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Q 19: Which term of the Arithmetic Progression 3, 10, 17will be 84 more than its 13th term?

Answer»

a13=a+(n-1)da13=3+(13-1)7=3+12(7)=3+84=87an=a13+84an=87+84an=171

an=a+(n-1)d171=3(n-1)7171-3=7n-7171-3+7=7n175=7n175/7=n25=n

25th term of the given AP will be 84 more than its 13thterm.



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