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Q 13: Find the value of m so that m2, 4m- 6 and 3m 2 are three consecutive terms of an A.P |
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Answer» If a , b , c are in A. P then b - a = c - b m + 2 , 4m - 6 , 3m - 2 are A. P 4m - 6 - ( m + 2 ) = 3m - 2 - ( 4m - 6 ) 4m - 6 - m - 2 = 3m - 2 - 4m + 6 3m - 8 = - m + 4 3m + m = 4 + 8 4m = 12 m = 12/4 m = 3 |
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