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Q 13: Find the value of m so that m2, 4m- 6 and 3m 2 are three consecutive terms of an A.P

Answer»

If a , b , c are in A. P then

b - a = c - b

m + 2 , 4m - 6 , 3m - 2 are A. P

4m - 6 - ( m + 2 ) = 3m - 2 - ( 4m - 6 )

4m - 6 - m - 2 = 3m - 2 - 4m + 6

3m - 8 = - m + 4

3m + m = 4 + 8

4m = 12

m = 12/4

m = 3



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