cot x=3/4=b/ph=√3^2+4^2=√9+16=√25=5cosec x=h/p=5/4cos x=b/h=3/54×5/4+5×3/5=5+3=8

8 is the right answer

8 is the correct answer......

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8 is the correct answer.......

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8 is the right answer

cosec x =5/4cos x=3/54*5/4+5*3/5=8

8 is the right ans.....

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8 is the correct answer

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ans. will be 8.

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the answer of this question will be 16

8 is the Right answer

8

in question perpendicular is 4 base is 3so by Pythagoras theorem hypotenuse is 5 hence in third quadrant cosec and cos is negative so answer is -8

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correct ans is 8 use pythogoras to theorem

8 is the right answer.

your questions is answer 15

your question is answer 8

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Answer is 32/3

since cot theta =b/p so first find h and put in cosec theta =h/p and cos theta =b/h and solve get answer 8

cot theta=3/4 so cosec theta= root over 1+9/16= 5/4 and sin theta = 4/5 so cos theta = root over 1-16/25=3/5 so 4cosec theta +5 cos theta =5+3=8

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4*5/4+5*5/3= 20/3 answer

(4*5/4)+(5*3/5)=8 is right

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so simple s right answer is 8.that mind solution.

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value of 4 cosecx+5cosx=-8