Q-1. The cost of 4 m of a certain cloth is Rs. 228a. Find the cost of

1.	Q-1. The cost of 4 m of a certain cloth is Rs. 228a. Find the cost of 15 m of the same clothb. How many metres of this can be bought for Rs. 627Q-2. The length and breadth of a rectangle are in ratio 5:4. If its breadth is 80cm find the length.Q-3. Find x of x, 36 and 27 are in continued proportion.PLEASE ANSWER MY QUESTION :):):):):):)
Answer» 1. Given Cost of 4m CLOTH = RS 228 Now, cost of 1 m cloth = 228/4 = Rs 57 a ) Cost of 15 m of the cloth = 15 × 57 = Rs 855 $Let \: x \:m \: of \:cloth \: bought \:at \:Rs \:627$ $x = \frac{627}{cost \:of \:1\:m \:cloth }\\= \frac{627}{<klux>57</klux>} \\= 11\:m$ $Let \: l \:and \: b \:are \: length \:and \: breadth \\of \: a \: rectangle$ $l : m = 5 : 4 \: (given)$ $Let \: l = 5x , \:and \: b = 4x$ $b = 80 \:cm \:(given)$ $\implies 4x = 80$ $\implies x = \frac{80}{4} = 20$ $Now, \: l = 5x = 5 \times 20 = 100 \:cm$ $3 ) x , 36 \:and \: 27 \: are \: in \: continued \\proportion$ $\pink { If \: a,b\:c \:are \:in \: continued }\\\pink {proportion \:then \:b^{2} = ac }$ $\implies 36^{2} = x \times 27$ $\implies x = \frac{ 36 \times 36 }{27} \\= 48$ •••♪