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Q. 1. In the given figure, if Z BAC 340,LBCE-1630, then find the value of L ACB,LABC and LDBC.0340163

Answer»

ACB + BCE = 180° [Linear angles]ACB = 180° - 163°ACB = 17°

ABC + ACB + BAC = 180° [Triangle sum property]ABC = 180° - 34° - 17° ABC = 129°

DBC + ABC = 180°. [Linear angles]DBC = 180° - 129°DBC = 51°



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