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Q.(1)Find the roots of the following quadratic equations by factorization(x - 4)(x + 2) = 0(4,-2)(i)(2x + 3)(3x - 7) = 0(iii)9x2 - 3x - 2 = 0310x=3(v)413x? + 5x - 23 = 0(vi)S2x2 – 3x-202=0.(1.12)(1.73)(vii) a?x? - 3abx + 2b2 = 0(viii) x? - (12+1)x + V2 = 0(ix) x2 - (V3 + 1)x + V3 = 0(x) ax + (na? – 3b)x – 12ab = 0(xi) 2 - 2x + 6 = 04+3 3x-2(1232) |
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Answer» (x+4)(x-2)0either x+4=0 , x= -4or x-2=0 , x= 2roots are (4,2)2)(2x+3)(3x-7)0either 2x+3=02x= -3x= -3/2or 3x-7=03x= 7x= 3/7roots are ( -3/2,3/7)3)9x^2-3x-2=09x^2-6x+3x-2=03x(3x-2)+1(3x-2)=0(3x-2)(3x+1)=0either 3x-2=03x= 2x= 2/3or 3x+1=03x= -1x=. -1/3roots are ( 2/3, -1/3)4) 1)(x+4)(x-2); x=4; x=-2; 2)(2x+3)(3x-7); 2x=-3; x=-3/2; 3x=7; x=7/3 (-3/2, 7/3) 3)9x^2-3x-2=9x^2-6x+3x-2=0; 3x(3x-2)+1(3x-2); (3x+1)(3x-2); 3x=-1:;x-1 x=-1/3, 3x=2; x=2/3; 5) |
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