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px+qy=40 is a chord of minimum length of the circle (x−10)2+(y−20)2=729. If the chord passes through (5,15), then p2019+q2019 is equal to |
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Answer» px+qy=40 is a chord of minimum length of the circle (x−10)2+(y−20)2=729. If the chord passes through (5,15), then p2019+q2019 is equal to |
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