Pure water vapour is trapped in a vessel of volume 10 cm3 . The relat

1.	Pure water vapour is trapped in a vessel of volume 10 cm3 . The relative humidity is 40%. The vapour is compressed slowly and isothermally. Find the volume of the vapour at which it will start condensing.
Answer» RH=VP/SVP The point where the vapour starts condensing, VP = SVP We know P₁V₁ = P₂V₂ R_H SVP × 10 = SVP × V₂ => V₂ = 10R_H => 10 × 0.4 = 4 cm³

Pure water vapour is trapped in a vessel of volume 10 cm3 . The relative humidity is 40%. The vapour is compressed slowly and isothermally. Find the volume of the vapour at which it will start condensing.

Answer»

RH=VP/SVP

The point where the vapour starts condensing, VP = SVP
We know P₁V₁ = P₂V₂
R_H SVP × 10 = SVP × V₂ => V₂ = 10R_H => 10 × 0.4 = 4 cm³