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Pulling force making an angle `theta` to the horizontal is applied on a block of weight `W` placed on a horizontal table. If the angle of friction is `alpha`, then the magnitude of force is `alpha` , then the magnitude of force required to move the body is equal toA. `(Wsinalpha)/(gtan(theta-alpha))`B. `(Wcosalpha)/(cos(theta-alpha))`C. `(Wsinalpha)/(cos(theta-alpha))`D. `(Wtanalpha)/(sin(theta-alpha))` |
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Answer» Correct Answer - C |
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