puleentage increase in thesurlaca1. A closed iron tank 12 m long, 9 m

1.	puleentage increase in thesurlaca1. A closed iron tank 12 m long, 9 m wide and 4 m deep is to be made Deteminecost of iron sheet used at the rate of 2 5 per metre sheet, sheet being 2 m wideby making, Ravish wanted to make a temporary shelter for his carstructure with tarpaulin that covers all the four sid
Answer» Given that length of theclosed iron tank = 12 m. Breadth of the closed iron tank = 9 m The height of the closed iron tank = 4 m. Total Surface Area of the tank = 2[lb + bh + hl] = 2[12×9+9×4+4×12] = 384 Area of the rectangular iron sheet = 384So that length × breadth = 384 But the breadth of sheet = 2 m (given) ∴ length = 384 / 2 = 192 m . Given that cost of iron, the sheet used at the rate of Rs 5 per metre. The total cost of the sheet = Rs. (192 × 5) = Rs. 960.

puleentage increase in thesurlaca1. A closed iron tank 12 m long, 9 m wide and 4 m deep is to be made Deteminecost of iron sheet used at the rate of 2 5 per metre sheet, sheet being 2 m wideby making, Ravish wanted to make a temporary shelter for his carstructure with tarpaulin that covers all the four sid

Answer»

Given that length of theclosed iron tank = 12 m.

Breadth of the closed iron tank = 9 m

The height of the closed iron tank = 4 m.

Total Surface Area of the tank = 2[lb + bh + hl] = 2[12×9+9×4+4×12] = 384

Area of the rectangular iron sheet = 384So that length × breadth = 384

But the breadth of sheet = 2 m (given)

∴ length = 384 / 2 = 192 m .

Given that cost of iron, the sheet used at the rate of Rs 5 per metre.

The total cost of the sheet = Rs. (192 × 5) = Rs. 960.