1.

Pthen,2ence, the numbers are 21,4. Find four numbers forming a GP. in which the third term is gterm by 9 and the second term is greater than 4 term by 18.L. Let the four terms of G.P. be a, ar,ar2,arven:

Answer»

Let the first term be a and the ratio r.

The four terms then are a,ar,ar^2 and ar^3

given , ar^2 = a + 9 ….(1) and

ar=ar^3+18 …. (2)

from (1), a*(r^2–1)=9…(3)

from (2), ar(r^2–1)=-18..(14)

(3)/(4) gives r=-2

substituting this in (1) 4a=a+9=>a=3.

So the terms are 3,-6,12,-24

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