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PT.Seco - cosecoSecot coseco |
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Answer» cotx=3/4; tan=(4/3); sin x=4/5; cos(3/5); cosecx=5/4; secx=5/3; Vsecx- cosecx/ secx+ cosecx= V(5/3-(5/4)/(5/3)+(5/4)= V5(4)-5(3)/12/5(4)+5(3)/12= V20-15/20+15=V5/35= V5/7×5=1/V7 cotA= 3/4cosA/sinA=3/4cosA/3= sinA/4=k(let)cosA= 3ksin^2A= 4ksecA+CosecA= 1/sinA+1/cosA= cosA+sinA/sinAcosA= 3k+4k/3k×4k= 7k/12k^2= 7/12ksecA-cosecA= 1/cosA-1/sinA= sinA-cosA/sinAcosA= 4k-3k/3k+4k= k/12k^2= 1/12k√secA-cosecA/secA+cosecA= √1/12k /7/12k= √1/7 I don't know answer. |
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