Pt(s)∣M(s)∣M3+(aq,0.002 mol L−1)∥Ag+(aq,0.01 mol L−1)∣Ag(s – InterviewSolution

1.	Pt(s)∣M(s)∣M3+(aq,0.002 mol L−1)∥Ag+(aq,0.01 mol L−1)∣Ag(s)The emf of the given cell is found to be 0.42 V at 25∘C. Calculate the standard potential of the half reaction.M3+(aq) + 3e−→M(s)Given:E0Ag+/Ag = 0.80 V
Answer» $P t (s) ∣ M (s) ∣ M^{3 +} (a q, 0.002 m o l L^{- 1}) ∥ A g^{+} (a q, 0.01 m o l L^{- 1}) ∣ A g (s)$ The emf of the given cell is found to be $0.42 V$ at $25^{\circ} C$ . Calculate the standard potential of the half reaction. $M^{3 +} (a q) + 3 e^{-} \to M (s)$ Given: ${E^{0}}_{A g^{+} / A g} = 0.80 V$

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